You need to iterate 8 times to create each row. Inside this loop, you will determine what values to add based on the row index Apply Logic for Pieces vs. Blanks Pieces (1s) statement to check if the current row index is less than 3 (top) OR greater than 4 (bottom). Blanks (0s) statement for the middle rows. Example Implementation
: Forgetting that the middle two rows (index 3 and 4 in an 8-row grid) must remain empty (0s). Bypassing Assignment
: Since the CodeHS canvas is 400 pixels wide and you need 8 circles, each "cell" is 50 pixels wide. The radius must be 25 . 9.1.6 checkerboard v1 codehs
grid and populating it with a specific checkerboard pattern using nested loops and conditional logic.
will fail the autograder. You must actually modify the list elements. Indexing Errors: Remember that Python indices start at grid has indices ranging from Middle Rows: Ensure rows You need to iterate 8 times to create each row
for row in board: print(" ".join(row))
Check that your loop runs exactly 8 times. If it goes to 10, the circles will disappear off the right side. Blanks (0s) statement for the middle rows
Are you a coding enthusiast looking to enhance your skills in app development and game design? Look no further than the 9.1.6 Checkerboard V1 CodeHS. This intriguing topic has been making waves in the coding community, and we're here to dive deep into its world.
Ensure you are actually changing board[i][j] = 1 rather than just printing, or you won't pass the autograder.
You need to target rows 0–2 (top three) and rows 5–7 (bottom three). For these specific rows, you will use a nested loop to flip every other 0 to a 1 .
grid populated with zeros. This sets up the structure of the board. board = [] for i in range(8): board.append([0] * 8) Use code with caution. Step 2: Implement Nested Loops You need to visit every cell in the grid. A nested loop is the best way to do this.